3/4(t+3)(8t-4)=6t^2+15t-9

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Solution for 3/4(t+3)(8t-4)=6t^2+15t-9 equation: 



3/4(t+3)(8t-4)=6t^2+15t-9

We move all terms to the left:

3/4(t+3)(8t-4)-(6t^2+15t-9)=0



Domain of the equation: 4(t+3)(8t-4)!=0

t∈R



We get rid of parentheses

-6t^2+3/4(t+3)(8t-4)-15t+9=0

We multiply parentheses ..

-6t^2+3/4(+8t^2-4t+24t-12)-15t+9=0

We multiply all the terms by the denominator


-6t^2*4(+8t^2-4t+24t-12)-15t*4(+8t^2-4t+24t-12)+9*4(+8t^2-4t+24t-12)+3=0

Wy multiply elements

-24t^3(+-60t^2(++36t(++3=0

We do not support etpression: t^3(

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